(4x^2-2x+5)(3x+1)=

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Solution for (4x^2-2x+5)(3x+1)= equation: 


Simplifying
(4x2 + -2x + 5)(3x + 1) = 0

Reorder the terms:
(5 + -2x + 4x2)(3x + 1) = 0

Reorder the terms:
(5 + -2x + 4x2)(1 + 3x) = 0

Multiply (5 + -2x + 4x2) * (1 + 3x)
(5(1 + 3x) + -2x * (1 + 3x) + 4x2 * (1 + 3x)) = 0
((1 * 5 + 3x * 5) + -2x * (1 + 3x) + 4x2 * (1 + 3x)) = 0
((5 + 15x) + -2x * (1 + 3x) + 4x2 * (1 + 3x)) = 0
(5 + 15x + (1 * -2x + 3x * -2x) + 4x2 * (1 + 3x)) = 0
(5 + 15x + (-2x + -6x2) + 4x2 * (1 + 3x)) = 0
(5 + 15x + -2x + -6x2 + (1 * 4x2 + 3x * 4x2)) = 0
(5 + 15x + -2x + -6x2 + (4x2 + 12x3)) = 0

Combine like terms: 15x + -2x = 13x
(5 + 13x + -6x2 + 4x2 + 12x3) = 0

Combine like terms: -6x2 + 4x2 = -2x2
(5 + 13x + -2x2 + 12x3) = 0

Solving
5 + 13x + -2x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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